10-ProjCobMadParte6

7/25/2019 10-ProjCobMadParte6

1/29

Emenda do banzo inferior:(MONTEIRO, J.C.R. Tesouras detelhado. Rio de Janeiro: Intercincia)

20e18nsosentre

10e8nsosentre

"

kgf81,9600N810 =

cunhasdepares2paresden

875,12560.281,9600

N.2Nparesden

cm7,5h/cm20a/cm20)x(4:cunhadaSeo

paran-do-PinhodeCunhas,,

absorvido

810

=

==

==

=


2/29

Concluso: devido ao tamanho de 200 cm, utilizar outro

sistema de emenda.

200 cm

20 20 20 20 20 20 20 20 20 20

5

5

cm55,73

2b

3

2==

Parafusos de presso 3/8

7,5 = b


3/29

Dimetro do parafuso: (NBR 7190 artigo 67)

mn

875,125,15,75,7bb

cm9,0mm9

==

( )"8/5cm60,1 ==

Esforo admissvel:

==

==

kgf40,422,601.165.165

kgf00,408,601.,57.34.b.34F 22P


4/29

Quantidade de parafusos:

77,1108,004.2

81,9600

F.2

Nparafusosden

P

810 ===

parafusos12parafusosden

Concluso: sendo o dimetro do parafuso = 1,60 cm,

deveremos aumentar a altura do perfil do banzo inferiorpara 10 cm.

cm2,117;cm6,44

cm8,43;cm2,41,5

==

==

4

3

5,1

5,1

7


5/29

10=h

11 5 6,5 6,5 6,5 11,5 11,5 6,5 6,5 6,5 11,5

111 cm

6,56,5 cm6 56 5

Cobrejunta

cm8,3cm75,32

5,7

2

b

==

5

3,8

7,5=b

7,5=b

3,8


6/29

PERPENDICULAR S FIBRAS:Seco til: 2 parafusos = 1,60 cm (alinhados)

=5 =310

2,5=1,5

Tenso de servio:

( ) 2uu cm00,51S1,60.210.5,7S ==

2stp

u

810stp kgf/cm13,94

00,51

41,4800

S

N===

7,5


7/29

Tenso admissvel: (NBR 7190 artigo 53)

2f

f

)paran-do-Pinho(kgf/cm582

aresistncidelimite-estticaflexo

=

Verificao de dimensionamento:

2ftp kgf/cm30,87582.15,0.15,0 ===

)NEGATIVO(30,8713,94tpstp >


8/29

PERPENDICULAR S FIBRAS:Seco til: 2 parafusos = 1,60 cm (alinhados)

36,512,53

Tenso de servio:

( ) 2uu cm75,69S1,60.25,12.5,7S ==

2stp

u

810stp kgf/cm82,68

75,69

41,4800

S

N===

7,5


9/29


2f

f



=


2ftp kgf/cm30,87582.15,0.15,0 ===

)OK(30,8782,68tpstp


10/29

PARALELO S FIBRAS:Seco til:

7,5

ccm

Tenso de servio:

c.5,7Su =

c.7,5.4

41,4800

S.4

N

u

810sci ==


11/29

Tenso admissvel: (NBR 7190 artigo 59b)

2r

r


aresistncidelimite-fibrassparalelooisalhamentc

=


2rci kgf/cm45,936.15,0.15,0 ===

cm17ccm93,16c

45,9c.57,.4

41,4800ci

sci

=


12/29

12,5=h

17 6,5 6,5 6,5 17 17 6,5 6,5 6,5 17

133 cm

6,56,5 cm6 56 5

cm8,3cm75,32

5,7

2

b

==

5

3,8

7,5=b

7,5=b

3,8


13/29

5.5-Dimensionamento das ligaes:

Ligao do N 1:

P1

Chapuz

N12 = 1021,34 kgf

cm25,6a

2

5,12

2

ha 12 ===

N 1

Contra-frechal

c

aEstribo

2 perfis (3x5)

2


14/29

PERPENDICULAR S FIBRAS:Seco til:

6,25 = a

11,2517,5

Tenso de servio:

2uu cm537,84S25,11.5,7S ==

2stp

u

13stp kgf/cm17,6

4,3758.2

57,1041

S.2

N===

7,5cm


15/29


2f

f



=


2ftp kgf/cm30,87582.15,0.15,0 ===

)OK(30,8717,6tpstp


16/29

PARALELO S FIBRAS:Seco til:

7,5

cm

Tenso de servio:

c.5,7Su =

c.,57.2

57,1041

S.2

N

u

13sci ==


17/29


2r

r



=


2rci kgf/cm45,936.15,0.15,0 ===

cm10ccm35,7c

45,9c.5,7.2

57,1041ci

sci

=


18/29

Ligao do N 13:P3

Chapuz

N 13


19/29

MONTANTE:

N1213 = 814,14 kgfb = 3,8 cm

r r u : NBR 7190 artigo 67

( )"

mn

8/3cm95,0

95,063,0

4

8,3

6

8,3

4

b

6

b

cm9,0mm9

==

==


20/29

Esforo admissvel:

kgf91,14895,0.165.165

kgf74,12295,0.8,3.34.b.34F 22P

==

==

kgf98,121

1,311cos.05,5911,311sen.22,741

05,591.22,741F

cos.Fsen.F

F.F

F

kgf19,21195,0.,951.120..120kgf59,10595,0.8,3.,951.15.b..51F

22

2N

2P

NP

22N

=

+

=

+=

====


21/29


parafusos767,698,121

14,814

F

Nparafusosden 1213 ===

Concluso: aumentar a base do perfil para b = 5 cm

( )"2/1cm25,1

25,183,04

5

6

5

4

b

6

b

==


22/29

Esforo admissvel:

kgf81,2575,21.165.165

kgf50,2125,21.5.34.b.34F 22P

==

==

kgf68,209

1,311cos.50,7511,311sen.12,502

57,501.12,502F

cos.Fsen.F

F.F

F

kgf00,3155,21.,681.120..120kgf50,1575,21.5.,681.15.b..51F

22

2N

2P

NP

22N

=

+

=

+=

====


23/29


parafusos488,368,209

14,814

F

Nparafusosden 1213 ===

Concluso: aumentar a altura do perfil para h = 7,5 cm

7,5 cmc


24/29

PERPENDICULAR S FIBRAS:

Seco til: 2 parafusos = 1,25 cm (alinhados)

1,875 =1,53,75 =37,5

1,875=1,5

Tenso de servio:

( ) 2uu cm00,25S1,25.2,57.5S ==

2stp

u

1213stp kgf/cm57,32

00,25

14,814

S

N===

5


25/29


2f

f



=


2ftp kgf/cm30,87582.15,0.15,0 ===

)OK(30,8757,32tpstp


26/29

PARALELO S FIBRAS:

Seco til:5

cm

Tenso de servio:

c.5Su =

c.5.4

14,814

S.4

N

u

1213sci ==


27/29


2r

r



=


2rci kgf/cm45,936.15,0.15,0 ===

cm38,21ccm31,4c

45,9c.5.4

14,814ci

sci

=


28/29

Ligao do N 14:

x3)

N1314 =1533,99 kgf

N1314 =1533,99 kgf

N1415 =2315,08 kgf

2 perfis (3x3)

2

1p

erfi

l(

N 14

N1214 =8156,03 kgf

N1214 =8156,03 kgf

Estribo: chapa (50 x 6) mm


29/29

Ligao do N 15:

Chapuz Chapuz

P3/2 P3/2

CumeeiraCumeeira

N1415 =2315,08 kgf

1p

erfil(2x3)

Estribo: chapa(50 x 6) mm

10-ProjCobMadParte6

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