1

Variantim 71 וריאנטים

April 2017

מקוריות: פתרונים והערות

Originals: Solutions & Comments

IRT judges: #2: Givi Mosiashvili (2017) #3: Zoran Gavrilovski (2016-7); #n: Viktor Volchek (2015-

7); Studies: Ofer Comay (2017) H#: Valery Gurov (2017); S#: TBD (2017-8)

Fairies: Alexander Bulavka (2017)

Editors: :עורכים

Orthodox: Evgeni Bourd

Fairies: Michael Grushko

Studies: Ofer Comay

evgbourd@gmail.com

bargrushko@bezeqint.net

ofercomay@gmail.com

יבגני בורדבעיות רגילות:

מיכאל גרושקובעיות אגדתיות:

עופר קומאיסיומים:

2915

Givi Mosiashvili

Georgia

#2vv 12+10

1.Qd3? [2.Sxf7#] 1...Qxe4 2.Qxe4# 1...Sg5 2.Bxf6# 1...cxd6 2.Re7#

1...Qxd6 2.Qd4# but 1...Ra8+! 1.Rxf6? [2.Re7#] 1...Qxe4 2.Sxf7# 1...Sg5

2.Re6# 1...Bxf6+ 2.Bxf6# 1...Sf4 2.gxf4# but 1...Qxd6!

1.Sxf6! [2.Sxf7#] 1...Qxe4 2.Re7# 1...Sg5 2.Sg4# 1...Bxf6+ 2.Bxf6#

1...Qxd6 2.Qc3#

Barnes, Dombrovskis theme, Rice +le Grand =Mosiashvili sintesis, changed

mates (Author)

2916

David Shtern

Petach Tikva

#2vvvv 8+7

1.Rf6? [2.Sc6#] but 1...dxe3! 1.Qd1? [2.Qxd4#] but 1...d3!

1.Qe1? zz but 1...Qg8! Try: 1.Qd3? [2.Qxd4#] but 1...Qd5!

1.Qc1! zz 1...Qe7/d7/c4 2.S(x)c4# 1...Qe6 2.Rxe6# 1...Qd5 2.Sd3# 1...Qe8

2.Sc4, Qc5/c7# 1...Qg8 2.Qc7# 1...dxe3 2.Qxe3# 1...d3 2.Qc3#

(1...Qc7 2.Re6, Qxc7# 1...Qb7/f8 2.Re6, Sc4# 1...Qa7/g7/h7 2.Re6, Sc4,

Qc5# 1...Qf6 2.Sc4, Qc5#)

The focal play by the BQ is aided by additional moves defending both c7 &

c4. However, there are too many moves by the BQ that give rise to more than

one mate (namely, duals). Can this be somehow corrected (PE)

2917

Evgeni Bourd

Givataim

#2v 8+12

1.Sfe4? [2.Qc3#] 1...Qc5 2.Qxc5# 1...Bxe4 2.Rxe4# 1...Rc6 2.Qd5# 1...Sb4

2.Qxb4# but 1...Re6!

1.Sge4! [2.Qc3#] 1...Qc5 2.Qxc5# 1...Bxe4 2.Rxe4# 1...Rg3 2.Qe5#

1...Sb4 2.Qxb4#

The choice of WS key is determined by the Nowotny refutation (PE)

'd'I'dNG dp0Rdpd' 'd'H'0'$ d'dPiPdr '1'dPd'g !'d')')n rd'd'd'd d'd'd'd'

'd'd'd'h d'd'dqd' '$'d'dpd H'd'ip)' 'd'0'H'd dpd')Pd' 'I'd'd'd dQd'd'd'

'd'd'dBI 1bd'$'0p pd'd'Hrd !'d'd'H' 'd'i'd'h d'd'd'd' 'dn0P)'g d'drd'd'

2

2918

Feliks Rossomakho

Russia

#3vv 9+11

1.Sb4 A? [2.Sd3#] but 1...Se5 a! 1.Sc7 B? [2.Se6#] but 1...Sg5 b!

1.O-O-O! [2.Qe4 [3.Qd4, Qb4, b4#] 2....cxd5 3.Qxd5# 2....b4 3.Qxb4#]

1...Se5 a 2.Sb4 A! [3.Bxd6#] 2....Sf7/c4/d3+ 3.S(x)d3#

1...Sg5 b 2.Sc7 B! [3.Bxd6#] 2....Sf7/e4 3.Se6# 2....f3 3.b4#

1...b4 2.cxb4+ Kb5 3.Qf1# Vladimirov theme

A castling key is always entertaining, especially when combined with such a

prominent theme as “Vladimiriov” (PE)

2919

Arieh Grinblat

Evgeni Bourd

Ashdod/Givataim

#3 12+9

1.f5! [2.Re8+ Kxf5 3.Re5#]

1...Bxf5 2.Rg4+ Bxg4 3.Rff4# 2....Kf3 3.Rxf5#

1...Rxc5 2.Sc3+ Rxc3 3.Rxe3# 2....Kd4 3.Bxc5#

Very good key leading to two Umnov variations (PE)

2920

L. Lyubashevsky

L. Makaronez

Rishon Lezion/Haifa

#3 8+6

1.Qe7! [2.Sg6+ Kg4 3.Qg5#]

1...Qxf5 2.Se2+ fxe2 3.Bg3#

1...Qg4 2.Sd3+ exd3 3.Qe3#

1...Qh1 2.Qg5+ Kxe5 3.f6#

1...Qh4 2.Sg6+ Kg4 3.Qxh4#

The black queen tries to correct its defenses and causes white to keep

changing its strategy (PE)

2921

Alexandr Kuzovkov

Russia

#3v 7+12

1.S1f2? [2.fxe5+ [A] Kd5 3.Rxc5 [C]#]

1...Sc4 a 2.bxc5+ [B] Kd5 3.Sb4#

1...Kd5 b 2.Rxc5+ [C] Kd6 3.fxe5 [A]#

1...Se4 c 2.Rxe5 [D] [3.Sxe4#] 2....Se4~ 3.bxc5#

1...exf4 2.Sxf4 [3.bxc5#] 2...Re6/cxb4,c4/Se4 3.Rxe6/Rd7/Sxe4# but 1...e4!

1.S1b2! [2.bxc5+ [B] 2....Kd5 3.Rxe5 [D]#]

1...Sc4 a 2.Rxc5 [C] [3.Sxc4#] 2....Sc4~ 3.fxe5#

1...Kd5 b 2.Rxe5+ [D] Kd6 3.bxc5 [B]#

1...Se4 c 2.fxe5+ [A] Kd5 3.Sf4#

A special combination featuring a 4-fold Shedey! In addition, there is

exchange of 2nd & 3rd white moves between threat & 1…Kd5 defenses (PE)

2922

Paz Einat

Nes Ziona

#3 10+10

1.Qa8 ! [2.Qa1 C+ Kf4 3.Bd2#]

1...Bxg1 2.Qe4 A+ fxe4 3.f4#

1...Sa7 2.Qd5 B+ exd5 3.Bd6# 2...Kf4 3.Bd2#

1...Kf4 2.Sh3 + gxh3 3.Qe4 A # 2...Ke5 3.Qa1 C#

1...Ba4 2.Rxe6 + Kxe6 3.Qd5 B # 2...Kf4 3.Bd2#

The two Q-sacrifice variations are the core of the problem. These are

combined with return of the 2nd moves, including the threat, as mates (author)

'd'd'G'd dpd'dnd' b0p4'd'0 dpiNd'd' 'd'd'0'$ dP)'d'd' 'd'd')Qg $'d'I'd'

'd'd'$Bd d'0'd'I' 'G'd'dNd dN)'d'd' ')'dk)bd d'4p0'$P ')pdpd'd d'd'd'dq

'd'd'd'd d'I'd'd' 'd'd'd'd dp!'HPd' 'd'Hpi') $'d'dpdq 'd'd'Gbd d'd'd'd'

bd'I'd'd d'd'$'dp 'dpi'd'4 $'0'0'dp ')'0')pd d'dNh'h' 'd'd'd'd d'dNd'd'

'dnd'd'd dQ)bd'I' '0'dp$'d d'd'ipdp 'GPd'dpd d'dpdPd' 'dNd'dRg d'd'd'H'

3

2923

Semion Shifrin

Nesher

#3 10+6

1.Qa8! [2.Rd4+ Kxd4/e5 3.Qd5#]

1...Qb5 2.Sf5 [3.Sg3#] 2...Bxf5 3.Bxf5# 2...Qxd5 3.Qxd5#

1...Sc7/xf6 2.Qa4+ Qxa4 3.Sxd6#

1...Qxe6 2.Rxd6+ Qd5+ 3.Qxd5# 2....Ke5 3.Sxf3#

1...Qg7+ 2.fxg7 ~ 3.Qa4#

Queen defense choice and good sacrifices (PE)

2924

Alberto Armeni

Italy

#3 8+9

1...d5 2.Bxe2+ c4 3.Se6# 2....Sxa4 3.Sb5#

1.Qa8? but 1...e6!

1.Qc6! [2.Qd5+ Sxd5 3.Sb5#]

1...e6 2.Qxd6+ Sd5 3.Sb5#

1...Rh5 2.Qe4+ Bxe4 3.Se6# 2....Sxe4 3.Sb5# 2....Rxe4 3.Sc2#

Nice Nowotny variation (PE)

2925

Jan Timman

Netherlands

Win 6+5

2926

Pavel Arestov

Russia

Win 4+5

2927

Michal Hlinka

Luboš Kekely

Slovakia

Draw B 5+3

'!Ndnd'd d'dqd'db ')'0B)'d d'dRd'I' 'd'dkd'H d'd'dpd' ')'d')'d d'd'd'd'

'I'd'd'd d'd'0'Hb '0'0'd'd d'0'd'd' QdBi'G'd HPh'dPd' 'd'drd'4 d'd'd'd'

'd'd'd'd d'd'd'd' 'd'd'd'd d'd'd'd' 'd'0'dBH 0'd'd')' Pd'0P0'I d'd'dkd'

'd'd'd'd d'd'd'd' 'd'd'd'd d'd'i'0p 'dB$'d'd d'd'dpd' 'dpd'I'd d'd'd'dN

'd'd'drd d'd')')' 'd'd'd'd d'drd'i' 'd'd'd'd d'd'd'I' 'd'd'HBd d'd'd'd'

4

2928

Steffen Nielsen

Martin Minski

Denmark/Germany

Win 9+9

2929

David Gurgenidze

Martin Minski

Georgia/Germany

Win 7+6

2930

Amatzia Avni

Eli Amit

G.Shmuel/Tel Aviv

Draw 8+8

2931

Peter S. Krug

Mario Garcia

Austria/Argentine

Win 6+8

rd'd'd'i 1'0'd'0' 'd'd'dPd hR)'d'dP 'd'0'd'$ d'g'dP0' 'd'd'dPd dQd'd'dK

'1'g'd'd 4Pd'0Bd' 'd'd'd'd d'd'd'd' 'd'd'd'd i'd'H'0' Pd'd'dRd HKd'd'd'

'd'dQ4kd d'd'dpdp 'd'1pd'd d'dNd'dB 'dRd')'d 0'd'd')' bd'd')'d d'd'd'dK

'd'dbi'd dp0'd'd' 'd'd'd'g d')'d'd' ')'d'd'd d'0Kh'!R Pd'0'd'd d'd'd'd'

5

2932

F. Abdurahmanovic

Zvonimir Hernitz

Bosnia/Croatia

H#2 2.1.1.1 8+11

1.dxc2!+ Sd6 2.cxd1=S Bb1#

1.Rxg2! Se3 2.Rg1 Rxg1#

Two line clearance solutions, but clearly the 1st solution is better (PE)

2933

Evgeni Bourd

Givataim

H#2 4.1.1.1 8+6

1.e5 Rd6 2.exf4 Re5#

1.Se5 Rxc2 2.Kd4 Rd6#

1.Sd2 Rf5 2.Qd3 Rxe6#

1.Kxf4 Rg5 2.e5 Rf6#

The half-battery is nicely used to give mates on a “plus” like squares (PE)

2934

Christer Jonsson

Sweden

H#2 2.1.1.1 5+5

1.Qg4 Rf7 2.Kc4 Rd7#

1.Qe4 Rg7 2.Kd4 Rg3#

Interferences for black king arrival square are well known, including the

black/white combination shown here, but this is admirably well constructed

(PE)

2935

Emanuel Navon

Holon

H#2 b)bd4e5 6+11

a) 1.Kd3 Rc7 2.Kc3 Rxh3#

b) 1.Kd4 Ra5 2.Kc5 Qg1#

Anticipatory direct pins by white and the black king makes two moves into a

double-pin (PE)

2936

Jean Haymann

Pardes-Hana

H#2 2.1.1.1 9+11

1.Qxc5 Sc4+ 2.Qd4 Sb2#

1.Rxf6 Qh8 2.Rf2 Sf3#

A very interesting concept: in each variation black captures a white piece on

the intended mating battery and moves away to enable the mate. However,

each solution shows unique strategy with self-pin as the central idea in the

first and interferences in the second (PE)

'd'4'd'd g'd'd'1b 'dnd'dkd d'd'd'dp 'd'dNGNd d'dpdp4' BdPIpdPd d'dRd'd'

Bd'd'd'd G')'d'd' n$'dpd'd dq$'d'dK ')nd')'d d'd'i'd' 'dpd'd'd d'd'd'd'

'dbd'dBG d'd'd'dR 'd'd'dqd I'0'd'd' 'd'd'd'$ d'dkd'd' 'd'd'd'd d'd'd'4'

qd'd'd'd $'dKd'!' 'd'0'd'h dnd'd'dR 'dbgPd'd )'d'i'dp '0p0'd'd d'd'd'd'

'dQd'd'd d'dpd'dp '1')'G'4 dpHPH'd' '0'd'd'0 dPi'd'd' Pd'd'd'0 d'I'd'gr

6

2937

Semion Shifrin

Nesher

H#2 5+6 b) in mate po. Bd6=b c) in mate pos. Sf3=n

a) 1.Bg3 ? d4+ 2.Kf4 d3+ ??

1.Bg5 Ba3 2.Kf4 Bd6#

b) in mating position of a) wBd6 = bBd6 1.Ke5 Kg7 2.Bf4 Sf3#

c) in mating position a) wSf3 = bSf3 1.Sg5 dc 2.Se4 d4#

Nice switchback in b) and good exploitation of the position for the further

solution (PE)

2938

Emil Klemanic

Slovakia

H#2 2.1.1.1 5+12

b) rd8=b

a) 1.Sxg7 Qxg7 2.Ke8 Sxc7#

1.c3 Qxc3 2.Sf6 Qxc7#

b) 1.Sxb5 Qxb5 2.Kc7 Sxe8#

1.e5 Qxe5 2.Sa8 Qxe8#

Two matching pairs showing harmony and unity (PE)

2939

Emanuel Navon

Holon

H#2 4+12 b) in mate pos. Pe4=R c) in mate pos. Rd7=B d) in mate pos. Be6=S

a) 1.Re6 b4 2.Rd6 e4#

b) after a) wP=R 1.Ra6 Re7 2.Bb6 Rxd7#

c) after b) wR=B 1.Bc5 Bc8 2.Bd6 Be6#

d) after c) wB=S 1.Bc5 bxa5 2.Rd6 Sxc7#

The move 1…b4 is the only one possible in the 1st solution but proves

constructive in the further two solutions and just to enable a tempo move the

4th solution (PE)

2940

Christer Jonsson

Sweden

H#3 2.1.1.1 3+5

1.Kg8 Bg1 2.hxg1=R Se4 3.Rg7 Sf6#

1.Kh6 Sb1 2.cxb1=B Kf7 3.Bh7 Be3#

Zilahi with minor promotions with excellent construction (PE)

'd'd'd'I d'd'd'd' 'd'dbd'd d'dnipd' 'd'd'g'd d'0Pd'd' 'd')'d'H d'G'd'd'

'db4nd'd )phkd'H' pd'0pd'd dNdrd'd' 'dpd'1'd d'd'd'd' '!'d'd'd d'd'I'd'

'd'd'd'h d'0pd'd' 'd'd'0'd 0PgkdK0' 'dr0rdpd dPd')'d' 'd'd'd'd d'd'd'd'

'd'dKd'g d'd'd'i' 'd'd'd'd d'G'd'dp 'd'd'd'd d'd'd'd' 'dpH'd'0 d'd'd'd'

7

2941

Menachem Witztum

Tel Aviv

H#3 4+13

b)B=S & b=n

a) 1.Bd1 Bg5 2.c1=S Bxf6 3.Bf3 Be5#

b) 1.Sg1 Sb3 2.c1=B Sd4 3.Sf3 Se2#

Successful twinning leading to unified solutions including two self-blocks on

f3 (PE)

2942 G. Voulgaris & I. Kalkavouras

Greece

H#4.5 2+10

1...Kd6? 2.Ka3! Bf7! 3.Bd3 Kd5 4.Bb1 Kc4 5.Ka2 5.Kb4# (??) d5! (Indian

theme)

1.....Be2? 2.Bd3! Bxf3 3.Bb1 Kc4 4.Ka3 Bd5 5.Ka2 Kb4#(??) Rb3!

(Platzweschel)

1....Bb5+! 2.Ka3! Bxd7 3.Bd3 Be6 4.Bb1 Kc4 5.Ka2 Kb4# (Herlin)

Two strategic maneuvers due to some reason fail, while a third one succeeds

in resolving the puzzle. (authors)

2943

Evgeni Bourd

Givataim

S#2 10+15

1.Sbd3! zz

1...Rxd3 2.Qd5+ Rxd5#

1...Qxd3 2.Qd6+ Qxd6#

Only two variations, but very interesting ones (PE)

2944

Daniele Gatti

Italy

S#5 9+7

1.Bd6! zz

1...Kb7 2.Rcxb6+ Ka8 3.Ra5 Ra6 4.Rb8+ Ka7 5.c5 Rxa5#

1...b5 2.Rc8+ Kb7 3.Rb8+ Kxa6 4.cxb5+ Ka5 5.Bxb4+ Kxb4#

The two variations show very different strategies (PE)

2945

Raffi Ruppin

Rehovot

#6 AntiCirce 9+6

1.Sg6? (2.Se7#) Bxb2(Bf8)!

1.b4 ! [2.b5#]

1...Ba6 2.b5 + Bxb5[bBb5c8] 3.b4 [4.b5#] 3...Ba6 4.b5+ Bxb5[bBb5c8]

5.Sg6 [6.Se7#] 5...Bxe5[bBe5f8] 6.Se5#

A nice logical problem: the two WP’s must be removed, and after 3.b4 black

does not have time for 3…Bc3 (PE)

'd'd'd'd d'd'd'd' 'd'dp0'd d'd'd'd' 'd'd'dp0 d'dPd'ip P0pdb0rd 1rG'd'dK

'd'd'd'd d'dpd'd' b0'd'd'd d'dKdpd' kdBd'd'd d'd'dn4' '0'd'd'd g'd'd'h'

'd'i'db$ dPd'd'dR 'd'dQ4'd d'I'd'dB 'H'd'd'G d'd'0pdp 'dp4q0p) d'Hbgbh'

kd'd'd'd 4'G'd'd' R0Rd'0'd d'd'dBd' '0Pd')'d dP0'd'd' Kdpd'd'd d'H'd'd'

'dbd'd'd G'0pdKd' 'dkH'd'd d'd')Pd' 'd'dPd'H dPd'dpd' ')'d'd'd g'd'd'd'

8

2946

Menachem Witztum

Tel Aviv

H#2 Circe 2 sol. 7+7

1.Sxg4[+wBf1] hxg4[+bSg8] 2.Sxe3 [+wRa1] Rxa5[+bRh8] #

1.Sxe3[+wRa1] fxe3[+bSb8] 2.Sxg4 [+wBf1] Bxb5[+bRa8] #

Perfect scheme with pins, circe-specific anticipatory line closures and fairy

mates (PE)

2947

Emanuel Navon

Holon

#2 b) S#2 10+6

c) H#2 d) Bg4f3

a) #2 : 1.Bxd7! zz 1...f5 2.Re6#

b) S#2 : 1.Rg6! zz 1...f5 2.Bf3 f4#

c) h#2: 1.f5 Sxd3 2.Kd5 Bf3#

d) h#2: +g4f3 1.f5 c6 2.dxc6 Sxc6#

with three different stipulations, and one twin, there are four different

continuations after the black’s move f5 (PE)

2948

Sébastien Luce

France

H==5 Circe 3+2

Locust Q Neut. pawn P

1.b1=Q Kb3 2.d1=Q+ Qxd1-e1(Qd8) 3.Qf8 Kc4

4.Ke8 Kd5 5.Qxb4-a5(Qb8)+ Ke6==

Nice final position in which the two kings and BQ are neutralized (PE)

2949

Janos Csak

Hungary

Ser-S#11 4+9

b)qe8d7

a) 1.Qxe2 2.Qxe8 3.bxa3 4.a4 5.a5 6.a6 7.a7 8.a8=S

9.Sb6 10.Sxc4 11.Qa4 + Bxa4 #

b) 1.Qxd1 2.b4 3.b5 4.b6 5.b7 6.b8=R 7.Rxb1 8.Rb4

9.Rxc4 10.Ra4 11.Qc2 + Sxc2 #

In both solutions W must remove, or control, the B pieces that would interfere

with the selfmate in the last move. (PE)

'dKd'd'd 1'd'd'd' kdPd'd'd 4r)'hnd' '0'd'dBd d'd'$'dP 'd'd')'d d'd'd'd'

'd'd'd'd d'dpd'd' 'd')'0'$ d')'i'dP 'Hpd'dBd d')pI'0' 'd')'dPd d'd'd'd'

'd'd'd'd d'd'dkd' 'd'd'd'd d'd'd'd' '!'d'd'd d'd'd'd' K)'0'd'd d'd'd'd'

'd'dqd'd d'd'd'd' 'd'd'd'd d'd'd'd' 'dnd'd'd g')'d'd' k)Qdpd'4 hrdbI'd'

9

2950

Emanuel Navon

Holon

HS#4.5 9+11

1...a3 2.Sc2 + Ka4 3.Sa1 Sb4 4.Ke1 Ba5 5.Ra8 Sc2,Sd3,Sa6#

An interesting approach to help-self mate: in the final position the BS gives

mate either by double checks or by interfering with WRa8 (PE)

2951

Paz Einat

Nes Ziona

#2vvvvv 16+15 Gr.Hopper < N.rider ±

B,R Hopper B,R

1.<f5-f1 ? [2.Sb5#] 1...<h7xc2 a + 2.Sa3xc2 A #

(1...<xf1 2.Rxd3# 1...<e2 2.<h8#) but 1...dxe5 !

1.<f5-d5 ? [2.±a6-b8#] 1...<h7xc2 a + 2.±a6xc2 B # but 1...b5 !

1.f3 ? [2.±a6-b8#] 1...<h2xc2 b + 2.±a6-xc2 B # but 1...b5 !

1.f4 ? [2.±g4xh2#] 1...<h2xc2 b + 2.±g4xc2 C # but 1...Rg1-g5 !

1.<e4 ? [2.±g4xh2#] 1...<c8xc2 c + 2.±g4xc2 C #

(1...<f1 2.Rxd3# 1...<e2 2.<h8#) but 1...Sxf2 !

1.<e2 ! ]2.Sb5#] 1...<c8xc2 c + 2.Sa3xc2 A # 1...<xe2 2.<h8#

In the 5 tries & solution there is a “dismantled” cyclical Zagoruiko (Rice

cycle) following the 6 different captures on c2 by the 3 grasshoppers on h7, h2

and c8. I believe this is the first time such a theme is realized. I didn’t find a

way to avoid the repeated refutation 1…b5 (author)

2952

R. Krätschmer F. Pachl

Germany

HS#2.5 Circe 7+7

b)bf8b8

a) 1...Qf4 2.Bxg5[+bRh8] + Kxg5 [+wBc1] 3.Qe7 + Bxe7[+wQd1] #

b) 1...Qxg4 2.Qxh5[+bRa8] + Kxh5 [+wQd1] 3.Rh1 + Bh2#

The circe is well used to create mating batteries, self-pins and square guards in

the two harmonious solutions (PE)

2953

Eugene Rosner

USA

#2v AMU 10+6

1.Rb6 ? [2.Rb4 A #] 1...Qxa2 a 2.Rc3 B #

1...Sc2 2.Bxb3# 1...Ba7 2.Qxf7# 1...Bc7 2.Qxf7# but 1...Ra6 !

1.Re3 ! [2.Rc3 B #] 1...Qxa2 a 2.Rb4 A #

1...Sc2 2.Bxb3# 1...Bf4 2.Qxf7#

In AMU the mating, (but not checking), move may only be made by a unit

which is observed by precisely one enemy unit (including King)

A natural AMU Le Grand mechanism with subtle movement of the WR’s and

good thematic refutation (PE)

'd'g'dRd d'd'd')' 'dpdpd'd dp)p)'d' pi')')'d d'dndpd' pd'Ip)'d d'd'H'd'

Bd>d'd'd G'dR0Bd> ±0'0pd'= 0'd')<d' 'd<i'd±d H'0pd'd' K0P$')'? d>d'='4n

'd'I'g'd dpdPGQd' pd'd'd'd d'd'd'4r 'd'd'dNi d'd'd'1' 'd'd'd'd dBd'd'$'

rg'd'dQd dRd'drd' 'd'd'd'd )'G'd'd' 'dk)Pd'd dqd'dRd' Bd')'d'd h'I'd'd'

10

2954

Georgy Bakcsi

Hungary

Ser-S#14 3+9

1.e4 2.e5 3.e6 4.e7 5.e8=S 6.Sc7 7.Sxa6 8.Sxb4 9.Sc6

10.Sxa5 11.Sxb3 12.Sc5 13.Sxa4 14.Sb6 + axb6#

A precise capturing sequence after the WS promotion (PE)

2955

Semion Shifrin Nesher

H#3 2.1.1.. 2+3

a) Take&MakeChess

SymmetryCirce b) Take&MakeChess

FileCirce

a) 1.Bxe2-g3[+wSd7] Sxg3-e1[+bBb6] + 2.Kg4 Sxb6-f2[+bBg3] + 3.Kh4

Sf3# 1.Rh4 Sg3 2.Kxg3-h5[+wSb6] Sxc4-f7[+bBf5] 3.Bg4 Sf4#

b) 1.Kxe2-g1[+wSe1] Sg3 2.Bf1 Sxh5-h4[+bRh8] 3.Rxh4-g2[+wSh1]

Sf3# 1.Rh2 Sg3 2.Kxg3-h1[+wSg1] Se2 3.Bxe2-g1[+wSe1] Sg3#

2956

Sébastien Luce France

H#2 3.1.1.1 4+1

Circe

b)Qa1e1 Neut. Locust, pawn QP

a) 1.Ph2-h1=R + Re1 2.Pxe1=Q Qxe1-f1[+Qe1] #

1.Ke4 Kg4 2.Pd2-d1=Q + Qxd1-e1[+Qd8] #

1.Kf4 Pd4 2.Ph2-h1=B Qxd4 -e5[+Pd7] #

b) 1.Pd2-d1=N Ne3 2.Kf4 Qxe3 -e4[+nSb8] #

1.Pxe1=R[+Qe8] Kh3 2.Re4 Qxe4-e3[+Ra8] #

1.Ph2-h1=N Nf2 2.Pxe1=Q [+Qe8] nLxf2-g3[+Nb8] #

Nice neutral locust mates with a plethora of promotions (PE)

2957

Michael Grushko Kiryat Bialik

Ser-H#5 2.1.1.. 3+1

Parraincirce

PhantomChess GridChess

Neut. Lion Q Pawn P

1.Qc7-cxg5 2.Pe3-e7-e6[+Pg8=Q] 3.Qgd5 4.Pxd5

5.Qg8-d8-d7 [+Qa4] Pd5-d2-d4#

1.Qf4 2.Kxf4 3.Pe3-e7-e6 [+Qf7] 4.Qf7-f1-f5

5.Kxg5 Qc8 [+Pd8=B] #

The combination of fairy conditions allow unusual movements, but makes

following the combination, as well as the mating positions, rather difficult

(PE)

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'd'd'd'd d'd'd'd' 'd'd'd'd d'd'd'd' 'd'd'd'I d'd'dkd' 'd')'d') !'d'd'd'

'd'd'd'd d'!'d'd' 'd'd'd'd d'd'i')' 'd'd'd'd d'd')'d' 'd'd'd'd d'd'd'd'

11

2958

Michael Grushko Kiryat Bialik

Ser-H#5 0+1+3 PhantomChess GridChess

Parraincirce

Neutral Lion Q pawn P

b) Pc6c5 Ser-H#6

c) Pg4d4 Ser-H#5

d) Pg4e2 Ser-H#6 2 sol

a) 1.Kc7 2.Qxc6 3.Pg4-g7-g6 [+Pc8=Q] 4.Qe6 5.Qxg6 Qe6-b6[+Pd6] #

b) 1.Ke5 2.Kf4 3.Qc8-c1-h6 4.Kg3 5.Kh2 6.Pg4-gxh6 Pc5-c2-c4 [+Qh5] #

c) 1.Ke7 2.Pd4-dxc6 3.Kd8 [+Pb7] 4.Qh8 5.Qh8-hxb7 Pc6-c7[+Pb8=Q]#

d) 1.Pe2-e7-e6 2.Qf5 3.Kxe6 4.Qf5-d7[+Pc8=Q] 5.Ke7

6.nQxc6 Qd7-g7[+Pf6] #

1.Kc7 2.Qxc6 3.Kc7-d6[+Pd5] 4.Ke7 5.Kf6 6.Pe2-e7-e5 Pxe6 ep. #

My comment to the previous problem can be extended here, Michael is

finding ingenious ways to find and implement new mating schemes (PE)

2959

G. Bakcsi & J. Csak Hungary

Ser-S#19 3+9

1.Kf1 2.Ke2 3.Kd3 4.Kd4 5.Ke5 6.Kxf6 7.Kg6 8.f6 9.f7 10.f8=Q 11.Qxc8

12.Qxc1 13.Kg5 14.Kxh4 15.Kxg4 16.Kf3 17.Ke2 18.Kf1 19.Kg1 Rxc1 #

The WK is making its way back to its diagram square. The position of BBc1

forces move order as the WQ must capture the B before the WK can move to

g5 (PE)

2960

Georgy Bakcsi

Hungary

Ser-R#10 5+6

1.Kh7 2.Kh6 3.Kh5 4.Kh4 5.Kxh3 6.Kh4 7.Kh5 8.Kh6

9.Kh7 10.Kh8 Rxh2#

Switchback along the h-file driven by the need to re-pin the WR (PE)

2961

Sébastien Luce

France

H==4.5 Circe 3+2 Neut. Locust Q Rose N

1...Nd5 2.Qxd5-c6[+wNd8] Nb7 3.Qxb7-a8[+wNb8] Nf8

4.Qxf8-g8[+wNf8] + Kh4 5.h1=Q + Nh3 ==

The neutral Locust and the Rose combine forces to neutralize the BK (PE)

'dQd'd'd d'd'd'd' 'dPi'd'd d'd'd'd' 'd'd'dPd d'd'd'd' 'd'd'd'd d'd'd'd'

'dnd'd'd d'd'd'd' 'd'd'h'd d'd'dPd' 'd'd'dp4 d'd'd'0' pd'd'dPd irg'd'I'

'd'd'd'I d'd'd'd' 'd'd'd'd dpd'd'd' ')'d'd'd G'd'd'dp '$'d'dr) g'i'd'4'

Nd'd'd'd d'd'd'd' 'd'd'd'i d'd'd'd' 'd'd'dKd d'd'd'd' 'd'd'd'0 d'd'd'dQ

12

2962

G. Bakcsi & J. Csak Hungary

Ser-H#4 4+3

b)kd3d8

a) 1.Kc2 2.Kb2 3.Kxa1 4.Sb2 Sxb3#

b) 1.Kc7 2.Kb6 3.Kxa5 4.Rb6 Rxa4#

This Zilahi can be accomplished without twins (PE)

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