Report - Aula 5 – Quadril´ateros Not´aveis · MODULO 1 - AULA 5 Temos pelo teorema 5: ∆ABC ⇒MN kAC e MN = AC 2 ∆DAC ⇒PQ kAC e PQ = AC 2 ⇒MN kPQ e MN = PQ. Logo pelo teorema 2,

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