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Sistemas de Numeração - Ariel Diasarieldias.com/material/2019-2/SN/Aula1.pdf3β2 + d 2β1 + d 1β0 347 = 3x102 + 4x101 + 7x100 ou 347 = 3x100 + 4x10 + 7x1 1241 = 1x103 + 2x102 +
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