Seminar Eim Breviar 2011
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Transcript of Seminar Eim Breviar 2011
7/23/2019 Seminar Eim Breviar 2011
http://slidepdf.com/reader/full/seminar-eim-breviar-2011 1/20
BREVIAR DE CALCUL
Seminar 2 - Evaluarea
impactului de mediu
7/23/2019 Seminar Eim Breviar 2011
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Necesar de apă a. Apa menajerăNecesarul pt. consum iienico-sanitar este determinat
con!orm S"AS - urilor #i normativelor $n vioare% S"AS &'()*+, S"AS &'*&-+
Q zi med = Q sp. x N/1000 ( m³/zi)unde%
/ sp 0 ) l*1om 3i4 con!orm S"AS &'()*+,/ sp 0 2, l*1om 3i4 con!orm S"AS &'()*+,N& 0 + persoaneN2 0 &, persoaneQ zi med = 3,52 m³/zi = 0,12 l/s
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Necesar de apă menajeră
Necesarul pt. consum iienico-sanitar%% S"AS &'()*+, S"AS &'*&-+
Q zi med = Q sp. x N/1000 ( m³/zi)unde%
/ sp 0 ) l*1om 3i4 con!orm S"AS &'()*+,
/ sp 0 2, l*1om 3i4 con!orm S"AS &'()*+,N& 0 + persoaneN2 0 &, persoaneQ zi med = 3,52 m³/zi = 0,12 l/s
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Necesar de apăQ zi max = Kzi x Qsp x N/1000
unde% 53i 0 &62 con!orm S"AS &'*&-+
Q zi max = ,22 m³/zi = 0,15 l/s
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Necesar!l de apăpen"r! i#ienizare$es"iare
Q zi med = % sp x s!pra&/1000(m³/zi)
unde% 7 sp 0 2 l*mp sp8lat 1S"AS &'()*+,4
Supra!a9a 0 &, mpQ zi med = 0,3 m³/zi
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/ 3i ma 0 5 3i 7 sp supra!*&,,,1m:*3i46
unde% 7 sp 0 2 l*mp spalat 1S"AS &'()*+,4
Supra!a9a 0 &, mp 5 0 &62 1S"AS &'*&-+4
Q zi max = 0,3' m³/zi
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Necesar!l de apă pen"r! 0
can"ină
/ 3i med 0 / sp. N*&,,, 1 m:*3i4
unde% / sp 0 22 l*1om 3i4 con!orm S"AS
&'()*+,
N 0 + persoane
Q zi med = 0,5 m³/zi = 0,03
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/ 3i ma 0 53i /sp N*&,,,
unde% /sp 0 22 l*1om 3i4 con!orm S"AS
&'()*+, N 0 + persoane 53i 0 &62 con!orm S"AS &'*&-+
Q zi max = 1,03 m³/zi
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Necesarul de ap8 total Q zi med = 3,52 0,3 0,5 =
,'* m³/zi = 0,1' l/s = 11'
m³/an
Q zi max = ,22 0,3' 1,03
= 5,'1 m³/zi = 0,1+ l/s = 125m³/an
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erin-a de apă /s 3i med 0 5p 5s / 3i med 1m:*3i4
unde% 5p 0 coe;cient pierderi de ap8< 5p 0 &6& 1S"AS
&'*&-+4< 5s 0 coe;cient pentru nevoile proprii ale sistemului
de alimentare< 5s 0 &6,( 1S"AS &'*&-+4.
/s 3i med 0 6 m:*3i 0 ,6&+ l*s 0 &=,m:*an
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erin-a de apă /s 3i ma 0 5p 5s / 3i ma 1m:*3i4
unde% 5p 0 coe;cient pierderi de ap8< 5p 0 &6& 1S"AS
&'*&-+4< 5s 0 coe;cient pentru nevoile proprii ale sistemului
de alimentare< 5s 0 &6,( 1S"AS &'*&-+4.
/s 3i ma 0 =6= m:*3i 0 ,622 l*s 0 &=(=m:*an
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Evacuarea apelor uzate
menajereConsider>nd c8 ),% din necesarul de ap8
mena?er8 se evacuea38 la canali3are6
de@itele evacuate sunt% Q !z med = 0, x Qs zi med (m³/zi) / u3 med 0 ,6) 6 m:*3i 0 '6' m:*3i
0 &&&(6= m:*an 0 0,15 l/s Q !z max = 0, x Qs zi max (m³/zi) / u3 ma 0 ,6) =6= m:*3i 0 62) m:*3i
0 &'& m:*an 0 0,1 l/s
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Concentraţii de poluanţi în
apele uzate ncen"ra-ia de ma"erii n s!spensie!nde
1/n = &rac-ia de "imp pe"rec!"ă de persană n incin"ă
c = '5 #/m x zi, cn&rm Nrma"i$ '' N = n!măr!l de persane care l!crează n cadr!l iec"i$!l!i = 13
Q!z n m3/zi
uzQ
Nc
n
1
uzC
⋅
⋅=
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pe !za"e menajere (i#ienic4sani"are) 4 Q!z = 0,01 l/s = 1,1*
m3/zi.
!z= 20,* #/m3 = 20,* m#/dm3
1,17
1365
3
1uzC
⋅
⋅=
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ei"!l masic de ma"erii n
s!spensie
6c = !z x Q!z
c 0 2',6(' *m- &6&( m-*3i 02)&6== *3i.
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ncen"ra-ia de ma"eriir#anice, exprima"e prin
785
1/n = &rac-ia de "imp pe"rec!"ă de persană n incin"ă
i = 5 #/m x zi, cn&rm Nrma"i$ '' N = n!măr!l de persane care l!crează n cadr!l iec"i$!l!i = 13
Q!z n m3/zi
uzQ
Ni
n
1uzL
⋅
⋅=
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= 200 #/m3 = 200 m#/dm3 !z= 200 #/m3 = 200 m#/dm3
1,171354
31uzL ⋅
⋅=
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ei"!l masic de ma"eriir#anice, exprima"e prin
785
6785 = 9!z x Q!z
CB 0 2,, *m- &6&( m-*3i 0 2'*3i.
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Concentra9ii #i de@ite masice alepoluan9ilor din apele u3ate
mena?ere6 la evacuarea $ncanali3are
:N:;8<
7:;6>:
(#/zi)
8NN;<?:
(m#/l)
6
(N;
002)/2002
>!spensii
2)2 2'& ,,
785 2' 2,, ,,
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"E END