Limites Transformantes Limites Convergentes Limites Divergentes.
Limites trigonometricos1
Transcript of Limites trigonometricos1
Limites Trigonométricos Resolvidos Sete páginas e 34 limites resolvidos
1
Usar o limite fundamental e alguns artifícios : 1lim0
=→ x
senxx
1. x
xx senlim
0→= ? à
xx
x senlim
0→=
00 , é uma indeterminação.
xx
x senlim
0→=
xxx sen
1lim0→
=
xx
x
senlim
1
0→
= 1 logo x
xx senlim
0→= 1
2. x
xx
4senlim0→
= ? à x
xx
4senlim0→
=00 à
xx
x 44sen.4lim
0→= 4.
yy
y
senlim0→
=4.1= 4 logo
xx
x
4senlim0→
=4
3. x
xx 2
5senlim0→
= ? à =→ x
xx 5
5sen.25lim
0=
→ yy
y
sen.
25lim
0 25 logo
xx
x 25senlim
0→=
25
4. nx
mxx
senlim0→
= ? à nx
mxx
senlim0→
=mx
mxnm
x
sen.lim0→
=nm .
yy
y
senlim0→
=nm .1=
nm logo
nxmx
x
senlim0→
=nm
5. xx
x 2sen3senlim
0→= ? à
xx
x 2sen3senlim
0→= =
→
xx
xx
x 2sen
3sen
lim0
=→
xx
xx
x
22sen.2
33sen.3
lim0
.23
22senlim
33senlim
0
0 =
→
→
xx
xx
x
x . 1.23
senlim
senlim
0
0=
→
→
tt
yy
t
y =
23 logo
xx
x 2sen3senlim
0→=
23
6. sennxsenmx
x 0lim→
= ? à nxmx
x sensenlim
0→=
xnx
xmx
x sen
sen
lim0→
=
nxnxn
mxmxm
x sen.
sen.lim
0→=
nxnx
mxmx
nm
x sen
sen
.lim0→
=nm Logo
sennxsenmx
x 0lim→
=nm
7. =→ x
tgxx 0lim ? à =
→ xtgx
x 0lim
00 à =
→ xtgx
x 0lim =
→ xxx
xcossen
lim0
=→ xx
xx
1.cossenlim
0
xxx
x cos1.senlim
0→ =
xxx
xx cos1lim.senlim
00 →→ = 1 Logo =
→ xtgx
x 0lim 1
8. ( )11lim 2
2
1 −−
→ aatg
a= ? à ( )
11lim 2
2
1 −−
→ aatg
a=
00 à Fazendo
→→
−=01
,12
tx
at à ( )tttg
t 0lim→
=1
logo ( )11lim 2
2
1 −−
→ aatg
a=1
Limites Trigonométricos Resolvidos Sete páginas e 34 limites resolvidos
2
9. xxxx
x 2sen3senlim
0 +−
→= ? à
xxxx
x 2sen3senlim
0 +−
→=
00 à ( )
xxxxxf
2sen3sen
+−
= =
+
−
xxx
xxx
5sen1.
3sen1.=
+
−
xxx
xxx
.55sen.51.
.33sen.31.
=
xx
xx
.55sen.51
.33sen.31
+
− à
0lim→x
xx
xx
.55sen.51
.33sen.31
+
−=
5131
+− =
62− =
31
− logo
xxxx
x 2sen3senlim
0 +−
→=
31
−
10. 30
senlimx
xtgxx
−→
= ? à 30
senlimx
xtgxx
−→
= xx
xxx
xx cos1
1.sen.cos
1.senlim2
2
0 +→=
21
( )3
senx
xtgxxf
−= = 3
sencossen
x
xxx
−=
3cos
cos.sensen
xx
xxx −
= ( )xx
xxcos.
cos1.sen3
− =x
xxx
xcos
cos1.1.sen2
− =
xx
xx
xxx
cos1cos1.
coscos1.1.sen
2 ++− =
xxx
xxx
cos11.cos1.
cos1.sen
2
2
+− =
xxx
xxx
cos11.sen.
cos1.sen
2
2
+
Logo 30
senlimx
xtgxx
−→
=21
11. 30
sen11lim
xxtgx
x
+−+→
=? à xtgxx
xtgxx sen11
1.senlim 30 +++
−→
=
xtgxxxx
xxx
x sen111.
cos11.sen.
cos1.senlim 2
2
0 ++++→=
21.
21.
11.
11.1 =
41
( )3
11
x
senxtgxxf
+−+= =
xtgxxxtgx
sen111.sen11
3 +++
−−+ =xtgxx
xtgxsen11
1.sen3 +++
−
30
sen11lim
xxtgx
x
+−+→
=41
12. ax
axax −
−→
sensenlim = ? à ax
axax −
−→
sensenlim =
−
+
−
→
2.2
2cos.
2sen2
limax
axax
ax=
12
cos..
2.2
)2
sen(2lim
+
−
−
→
ax
ax
ax
ax= acos Logo
axax
ax −−
→
sensenlim = cosa
Limites Trigonométricos Resolvidos Sete páginas e 34 limites resolvidos
3
13. ( )a
xaxa
sensenlim0
−+→
= ? à ( )a
xaxa
sensenlim0
−+→
= 1
2cos.
.
2.2
2sen2
lim
++
−
−+
→
xax
ax
xax
aa=
12
2cos..
2.2
2sen2
lim
+
→
ax
a
a
aa= xcos Logo ( )
axax
a
sensenlim0
−+→
=cosx
14. ( )a
xaxa
coscoslim0
−+→
= ? à ( )a
xaxa
coscoslim0
−+→
= a
xaxxax
a
−−
++
−
→
2sen.
2sen2
lim0
=
−
−
+
−
→
2.2
2sen.
22sen.2
lim0 a
aax
a=
−
−
+
−→
2
2sen
.2
2senlim0 a
aax
a= xsen− Logo
( )a
xaxa
coscoslim0
−+→
=-senx
15. ax
axax −
−→
secseclim = ? à ax
axax −
−→
secseclim = ax
axax −
−
→
cos1
cos1
lim = ax
axxa
ax −
−
→
cos.coscoscos
lim =
( ) axaxxa
ax cos.cos.coscoslim
−−
→= ( ) axax
xaxa
ax cos.cos.2
sen.2
sen.2lim
−
−
+
−
→=
axxa
xaxa
ax cos.cos1.
2.2
2sen
.1
2sen.2
lim
−
−
−
+
−
→=
axxa
xaxa
ax cos.cos1.
2
2sen
.1
2sen
lim
−
−
+
→=
aaa
cos.cos1.1.
1sen =
aaa
cos1.
cossen = atga sec. Logo
axax
ax −−
→
secseclim = atga sec.
16. x
xx sec1lim
2
0 −→= ? à
xx
x sec1lim
2
0 −→=
( )xxxxx
cos11.
cos1.sen1lim
2
20
+−
→= 2−
( )
x
xxf
cos11
2
−= =
xx
x
cos1cos
2
−= ( )x
xxcos1.1
cos.2
−−= ( ) ( )
( )xx
xxx
cos1cos1.
cos1.cos1
1
2 ++−
− =
( )xxxx
cos11.
cos1.cos1
1
2
2
+−
−=
( )xxxx
cos11.
cos1.sen1
2
2
+−
Limites Trigonométricos Resolvidos Sete páginas e 34 limites resolvidos
4
17. tgx
gx
x −−
→ 1cot1
lim4π
= ? à tgx
gx
x −−
→ 1cot1lim
4π
= tgxtgx
x −
−
→ 1
11lim
4π
=tgx
tgxtgx
x −
−
→ 1
1
lim4π
=
tgxtgx
tgx
x −
−−
→ 1
)1.(1
lim4π
=tgxx
1lim4
−→
π= 1− Logo
tgxgx
x −−
→ 1cot1
lim4π
= -1
18. x
xx 2
3
0 sencos1lim −
→= ? à
xx
x 2
3
0 sencos1lim −
→= ( )( )
xxxx
x 2
2
0 cos1coscos1.cos1lim
−++−
→=
( )( )( )( )xx
xxxx cos1.cos1
coscos1.cos1lim2
0 +−++−
→=
xxx
x cos1coscos1lim
2
0 +++
→=
23 Logo
xx
x 2
3
0 sencos1lim −
→=
23
19. x
x
x cos.213senlim
3−→
π= ? à
xx
x cos.213senlim
3−→
π= ( )
1cos.21.senlim
3
xx
x
+−
→π
= 3−
( )x
xxfcos.213sen
−= = ( )
xxx
cos.212sen
−+ =
xxxxx
cos.21cos.2sen2cos.sen
−+ = ( )
xxxxxx
cos.21cos.cos.sen.21cos2.sen 2
−+− =
( )[ ]x
xxxcos.21
cos21cos2.sen 22
−+− = [ ]
xxx
cos.211cos4.sen 2
−− = ( )( )
xcoxcoxx
cos.21.21..21.sen
−+−
− = ( )1
cos.21.sen xx +−
20. tgx
xxx −
−→ 1
cossenlim4
π= ? à
tgxxx
x −−
→ 1cossenlim
4π
= ( )xx
coslim4
−→π
=22
−
( )tgx
xxxf−−
=1
cossen =
xx
xx
cossen1
cossen
−
− =
xx
xx
cossen1
cossen
−
− =
xxxxx
cossencoscossen
−− = ( )
xxx
xx
coscossen.1
cossen−−
− =
xxxxxsencos
cos.1
cossen−
−− = xcos−
21. ( ) )sec(cos.3lim3
xxx
π−→
= ? à ( ) )sec(cos.3lim3
xxx
π−→
= ∞.0
( ) ( ) )sec(cos.3 xxxf π−= = ( ) ( )xx
πsen1.3 − = ( )x
xππ −
−sen
3 = ( )xx
ππ −−
3sen3 = ( )
( )xx
−−
3.3sen.1
ππππ
=
( )( )x
xππ
πππ−
−3
3sen.1 à ( ) )sec(cos.3lim
3xx
xπ−
→= ( )
( )xxx
πππππ
−−→
33sen.1lim
3=
π1
22. )1sen(.limx
xx→∝
= ? à )1sen(.limx
xx→∝
= 0.∞
x
xx 1
1senlim
→∝= 1senlim
0=
→ tt
t à Fazendo
→+∞→
=0
1tx
xt
Limites Trigonométricos Resolvidos Sete páginas e 34 limites resolvidos
5
23. 1sen.3sen.2
1sensen.2lim 2
2
6 +−−+
→ xxxx
x π= ? à
1sen.3sen.21sensen.2lim 2
2
6 +−
−+→ xx
xxx π
=x
xx sen1
sen1lim6 +−
+→π
=
6sen1
6sen1
π
π
+−
+=
211
211
+−
+= 3− à ( )
1sen.3sen.21sensen.2
2
2
+−−+
=xx
xxxf =( )
( )1sen.21sen
1sen.21sen
−
−
+
−
xx
xx= ( )
( )1sen1sen
−+
xx =
xx
sen1sen1
+−+
24. ( )
−
→ 2.1lim
1
xtgxx
π = ? à ( )
−
→ 2.1lim
1
xtgxx
π = ∞.0 à ( ) ( )
−=
2.1 xtgxxf π =
( )
−−
22cot.1 xgx ππ = ( )
−
−
22
1xtg
xππ
=( )
−
−
22
2.1.2
xtg
x
πππ
π
=
( )x
xtg
−
−
1.2
22
2
π
πππ =
−
−
22
22
2
x
xtg
ππ
πππ à
( )
−
→ 2.1lim
1
xtgxx
π =
−
−
→
22
22
2
lim1
x
xtgx
ππ
πππ = ( )
tttg
t 0lim
2
→
π =π2 Fazendo uma mudança de variável,
temos :
→→
−=01
2 tx
xxt ππ
25. ( )xx
x πsen1lim
2
1
−→
= ? à ( )xx
x πsen1lim
2
1
−→
= ( )( )x
xx
x
πππππ
−−
+→ sen.
1lim1
=π2
( )x
xxfπsen
1 2−= = ( )( )
( )xxx
ππ −+−
sen1.1 = ( )
( )xx
x
−−
+
1sen
1ππ
= ( )( )x
xx
−−
+
1.sen.
1
ππππ
= ( )( )x
xx
πππππ
−−
+sen.
1
26.
−
→xgxg
x 2cot.2cotlim
0
π = ? à
−
→xgxg
x 2cot.2cotlim
0
π = 0.∞
( )
−= xgxgxf
2cot.2cot π = tgxxg .2cot =
xtgtgx
2=
xtgtgx
tgx
212−
= tgx
xtgtgx.2
1.2− =
21 2 xtg−
−
→xgxg
x 2cot.2cotlim
0
π =2
1lim2
0
xtgx
−→
=21
27. x
xxx 2
3
0 sencoscoslim −
→= 11102
2
1 ...1lim
ttttt
t +++++−
→=
121
−
( )x
xxxf 2
3
sencoscos −
= = 12
23
1 ttt
−
− = ( )( )( )11102
2
...1.11.
ttttttt
+++++−−− = 11102
2
...1 ttttt
+++++−
63.2 coscos xxt ==
→→
10
tx xt cos6 = , xt 212 cos= , 122 1sen tx −=
Limites Trigonométricos Resolvidos Sete páginas e 34 limites resolvidos
6
BriotxRuffini : 1 0 0 ... 0 -1 1 • 1 1 ... 1 1 1 1 1 ... 1 0
28. xxxx
x sencos12cos2senlim
4 −−−
→π= ? à
xxxx
x sencos12cos2senlim
4 −−−
→π= ( )x
xcos.2lim
4
−→π
= 4
cos.2 π− =
22.2− =
2−
( )xxxxxf
sencos12cos2sen
−−−
= = ( )xx
xxxsencos
11cos2cossen.2 2
−−−− =
xxxxx
sencos11cos2cos.sen.2 2
−−+− =
xxxxx
sencoscos2cos.sen.2 2
−− = ( )
xxxxx
sencossencos.cos.2
−−− = xcos.2−
29. ( )112
1senlim1 −−
−→ x
xx
= ? à ( )112
1senlim1 −−
−→ x
xx
= ( )( ) 1
112.1
1sen.21lim
1
+−−
−→
xx
xx
= 1
( ) ( )112
1sen−−
−=
xxxf = ( )
112112.
1121sen
+−
+−
−−
−
xx
xx = ( )
1112.
1121sen +−
−−− x
xx = ( )
( ) 1112.
1.21sen +−
−− x
xx =
( )( ) 1
112.1
1sen.21 +−
−− x
xx
30.
3
cos.21lim3
ππ−
−
→ x
x
x= ? à
3
cos.21lim3
ππ−
−
→ x
x
x=
−
−
+
→
23
23sen
.2
3sen.2lim3 x
x
x
x π
π
π
π=
.2
33sen.2
+ ππ= .
23
2sen.2
π= .
3sen.2
π = 3
23.2 =
( )
3
cos.21π
−
−=
x
xxf =
3
cos21.2
π−
−
x
x=
3
cos3
cos.2
π
π
−
−
x
x =
( )
−−
−
+−
23.2.1
23sen.
23sen2.2
x
xx
π
ππ
=
−
−
+
23
23sen.
23sen.2
x
xx
π
ππ
=
−
−
+
23
23sen
.2
3sen.2x
x
x
π
π
π
31. xxx
x sen.2cos1lim
0
−→
= ? à xxx
x sen.2cos1lim
0
−→
=x
x
x
sen.2lim3π
→= 2
Limites Trigonométricos Resolvidos Sete páginas e 34 limites resolvidos
7
( )xxxxf
sen.2cos1 −
= = ( )xx
xsen.
sen211 2−− =xx
xsen.
sen211 2+− =xxx
sen.sen.2 2
=x
xsen.2
32. xx
xx sen1sen1lim
0 −−+→= ? à
xxx
x sen1sen1lim
0 −−+→ =
xx
xxx sen.2
sen1sen1lim0
−++→
=1.211+
=1
( )xx
xxfsen1sen1 −−+
= = ( )( )xx
xxxsen1sen1
sen1sen1.−−+
−++ = ( )xx
xxxsen1sen1
sen1sen1.+−+
−++ =
( )x
xxxsen.2
sen1sen1. −++ =
xx
xxsen.2
sen1sen1 −++ = 1.211+ = 1
33. xx
xx sencos
2coslim0 −→
= 1
sencoslim0
xxx
+→
= 22
22
+ = 2
( )xx
xxfsencos2cos
−= = ( )
( )( )xxxxxxxsencos.sencos
sencos.2cos+−
+ = ( )xx
xxx22 sencossencos.2cos
−
+ = ( )x
xxx2cos
sencos.2cos + =
( )x
xxx2cos
sencos.2cos + = 1
sencos xx + = 22
22
+ = 2
34.
3
sen.23lim3
ππ−
−
→ x
x
x= ? à
3
sen.23lim3
ππ−
−
→ x
x
x=
3
sen23.2
lim3
ππ−
−
→ x
x
x=
3
sen3
sen.2lim
3π
π
π−
−
→ x
x
x=
3
23cos.
23sen.2
lim3
π
ππ
π−
+
−
→ x
xx
x=
33
23
3
cos.23
3
sen.2
lim3
π
ππ
π −
+
−
→ x
xx
x=
( )3
3.16
3cos.63sen.2
lim3
x
xx
x −−
+
−
→ π
ππ
π
35. ?