Analisis del Avión Airbus A380

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    Airbus A380 The SCUFF

    Chase Ashton Doug Hillson Dave Simon

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    Gate Box Requirement

    A380 AR = 7.53

    A340 AR = 9.21

    is proportional to

    andR is proportional to

    Range and L/D wouldbe %10.6 greater

    max

    D

    L

    If the A380 and A340 had

    the same wingspan

    max

    D

    L

    AR

    AR

    106.1

    53.7

    21.9=

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    Airfoil Selection

    Supercritical airfoilsconsidered

    Whitcomb and others

    Transonic Helicopter

    blades considered NLR-7223-43

    Boeing airfoils considered

    Only access to oldairfoils

    Company is verysecretive

    Choose most recentsupercritical airfoil

    SC(2)-0714

    The SC(2)-0714 airfoilappears relatively easy tomanufacture

    Depending on t/c

    Ran on Tsfoil2 Normal Mach number

    greater than 1.3

    Airbus and Boeing haveairfoils not accessible for

    this project Designed for M = .80or greater

    Probably work betterthan SC(2)-0714

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    NASA SC(2)-0714 AIRFOIL

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    NASA SC(2)-0714 AIRFOIL

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    Surface Area Calculation

    Diagram used to

    model the A380 in

    CAD

    Complex bodies of

    revolution modeled inInventor

    Planar bodies

    measured in AutoCAD

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    Calculation using

    FRICTION0

    DC

    21.6

    29.1

    22.3

    41.5

    231

    Reference Length (ft)

    0.6303138 (each)Engines (4)

    0.0932990Vertical Tail

    0.0814211Horizontal Tail

    0.08218284Wing

    0.11916050Fuselage

    Thickness/ChordWetted Area (ft2)Component

    Reference Area: 9380 ft2

    All surfaces assumed 100% turbulent flow

    Wing, Horizontal, Vertical Tail - Modeled as Planer Surfaces

    Fuselage, Engines Modeled as Bodies of Revolution

    Input Parameters

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    0

    2DD

    CCMIN

    =

    0D

    C

    Results

    0.601

    0.601

    0.605

    0.602

    0.600

    0.611

    0.689

    CL

    0.0322

    0.0324

    0.0326

    0.0324

    0.0322

    0.0334

    0.0424

    CDmin

    0.0161

    0.0162

    0.0163

    0.0162

    0.0161

    0.0167

    0.0212

    CD0

    18.650.9030000

    18.620.8930000

    18.510.8530000

    18.600.8025000

    18.680.7520000

    18.320.5010000

    16.260.105000

    L/D MaxMach NumberAltitude

    0DL

    CeARC =

    Cruise

    Calculation using

    FRICTION

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    LAMDES

    Used to find

    Minimum Drag CG Location

    Minimum CLTwist Distribution

    Section Cl distribution

    Root and Tip Camber

    e

    Input

    Same planform as FRICTION analysis

    Mach = 0.85 (Cruise)

    CD0 = 0.0163

    10 chordwise horseshoe vortices20 spanwise rows

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    0.00

    0.05

    0.10

    0.15

    0.20

    0.25

    0.30

    0.35

    0.40

    0.45

    0.50

    0 5000 10000 15000 20000 25000 30000 35000 40000

    Altitude (feet)

    CLRequired

    Best Cruise Altitude at M=0.85

    MTOGW

    _ Fuel

    Zero Fuel

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    0.0

    0.5

    1.0

    1.5

    2.0

    2.5

    3.0

    0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1

    y/(b/2)

    Twist(degrees)

    Linear Theory Twist DistributionTwist Distribution for minimum drag at Cruise CL

    Main Wing

    Tail

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    0.00

    0.05

    0.10

    0.15

    0.20

    0.25

    0.30

    0.35

    0.40

    0.45

    0.50

    -125-115-105-95-85-75-65-55-45-35-25-15

    Cl

    y

    Section CL Distribution

    Main Wing

    Tail

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    Root and Tip Mean Camber Lines

    0

    0.5

    1

    1.5

    2

    2.5

    0 0.2 0.4 0.6 0.8 1 1.2

    y/(b/2)

    %camber

    Tip Camber

    Root Camber

    75% Span Camber

    25% Span Camber

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    Stability e

    NP Neutral Point, aft CG limit for stability(107.6 ft aft of LE of Fuselage)

    10% Stable CG 10% forward of NP

    (fraction of mean chord)

    23% Stable LAMDES Minimum Drag Solution

    NP10% Stable

    4 Feet

    9.2 Feet

    23% Stable

    e = 0.74

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    References

    Airbus Website UIUC Airfoil Database

    AIAA-2003-2886

    Commercial Aircraft

    Software:

    LAMDES

    FRICTION

    VLMpc