π=π β(ππ’π΅/("Ξ±" ΙΈ "f c " β² ππ(1β0.59π)))
((ππ’ π΅) ππ )/Β² πΌ = "fβ²c" ππ^2 "bd Ο (1-0.59Ο)ΙΈ Β² "
(ππ’ )/ ="f'c bd ΙΈ Β² Ο (1-0.59Ο)"
β/1.1=γ l βγ (ππ’π΅/(16β0.9β210βπ΅/20 β0.14β(1β0.59β0.14)))
h = (π )/(4.01/βππ’)π= βπ΄π§+((π‘1βπ‘2))/2
Ε₯
Β²
ln(β(β([email protected])))
π=βπ΄π§ + (t1-t2)
bD ((1.25β245.00 π‘))/((0.25) (0.28 π‘/(ππ^2 )))=4375.00 ππΒ²
AZAP π/ππ=(245 π‘)/(30.3 π‘/π )Β²
h= k z= 4 12.65ln ln
(β(2+ππ@ππ)) β(π^β² π πππ)
β/1.1 = l β(β(ππ’ π΅@16β0.9β210βπ΅/20β0.14β(1β0.59β0.14)))
h = (π )/(4.01/βππ’)h = ( )/((4/β0.1) ) = ( π π)/12.65=β
h = (π )/β(4/0.13) = (π )/11.09=βh = (π )/((4/β0.11) ) = (π )/12.06=βh = ( )/((4/β0.1) ) = ( π π)/12.65=β
Vc = 0.27(2+4/π½π) β("fβ" π) ππ π
Vc = 0.27(2+"Ξ± d" /ππ) β("fβ" π) ππ πVc = 1.06β("fβ" π) ππ π
ΙΈVc = 0.75β0.53ββ280β100β9 ππ=5986.30 ππ=5.99 π‘
π= β2.85 + ((0,8β0,55))/2Β² = 2,987 m
π= β2.85 β ((0,8β0,55))/2Β² = 2,725 m
π=π β(ππ’π΅/("Ξ±" ΙΈ "f c " β² ππ(1β0.59π)))
((ππ’ π΅) ππ )/Β² πΌ = "fβ²c" ππ^2 "bd Ο (1-0.59Ο)ΙΈ Β² "
(ππ’ )/ ="f'c bd ΙΈ Β² Ο (1-0.59Ο)"
Ο = (π ππ¦ )/(π'π )
β/1.1=γ l βγ (ππ’π΅/(16β0.9β210βπ΅/20 β0.14β(1β0.59β0.14)))
h = (π )/(4.01/βππ’)π= βπ΄π§+((π‘1βπ‘2))/2 π= βπ΄π§ β((π‘1βπ‘2))/2
ln(β(β([email protected])))
bD ((1.25β245.00 π‘))/((0.25) (0.28 π‘/(ππ^2 )))=4375.00 ππΒ²
AZAP π/ππ=(245 π‘)/(30.3 π‘/π )Β²
β/1.1 = l β(β(ππ’ π΅@16β0.9β210βπ΅/20β0.14β(1β0.59β0.14)))β("Ο" π’)
h = (π )/((β(4@β0.11)) )=(π )/12.65=β
h = (π )/(4.01/βππ’)h = ( )/((4/β0.1) ) = ( π π)/12.65=β
h = (π )/β(4/0.13) = (π )/11.09=βh = (π )/((4/β0.11) ) = (π )/12.06=βh = ( )/((4/β0.1) ) = ( π π)/12.65=β
Vc = 0.27(2+4/π½π) β("fβ" π) ππ π
Vc = 0.27(2+"Ξ± d" /ππ) β("fβ" π) ππ ππ= β(ππ’/(40.5βπ))
π= β((2,38β10 )/(40,5β100)=7,67 ππ)β΅
ΙΈVc = 0.75β0.53ββ280β100β9 ππ=5986.30 ππ=5.99 π‘
π= β2.85 + ((0,8β0,55))/2Β² = 2,987 m
π= β2.85 β ((0,8β0,55))/2Β² = 2,725 m
((ππ’ π΅) ππ )/Β² πΌ = "fβ²c" ππ^2 "bd Ο (1-0.59Ο)ΙΈ Β² "
β/1.1=γ l βγ (ππ’π΅/(16β0.9β210βπ΅/20 β0.14β(1β0.59β0.14)))
π= βπ΄π§ β((π‘1βπ‘2))/2
h = (π )/((β(4@β0.11)) )=(π )/12.65=β
π= β(ππ’/(40.5βπ))
π= β((2,38β10 )/(40,5β100)=7,67 ππ)β΅
h = (π )/((β(4@β0.11)) )=(π )/12.65=β
π= β((2,38β10 )/(40,5β100)=7,67 ππ)β΅