Resoluções de Exercícios Pares - Cap 19 até Cap. 22 - Princípios de Física Vol. 3

8/2/2019 Resoluções de Exercícios Pares - Cap 19 até Cap. 22 - Princípios de Física Vol. 3

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Chapter 19

103

ANSWERS TO EVEN NUMBERED PROBLEMS

2. 514 kN

4. (a) 2 16 10 5. ×− N toward the other (b) 8 99 10 7. ×

− N away from the other

6. (a) 82.2 nN (b) 2.19 Mm/s

8. (a) 55.8 pN/C down (b) 102 nN/C up

10. (a) (–599i – 2 700j) N/C (b) (–3.00i – 13.5j) μ N

12. (a) 1 29 104. × N/Cj (b) − ×−3 86 10 2. j N

14. 1 59 106. × N/C toward the rod

16. (a) 6.64 i MN/C (b) 24.1 i MN/C(c) 6.40 i MN/C (d) 0.664 i MN/C , taking the axis of the ring as the x-axis

18. −k xeλ 0 0i/

20. (a) 2 00 10 10. ×− C (b) 1 41 10 10. ×

− C (c) 5 89 10 11. ×− C

22. (a) –1/3 (b) q q1 20 0< > ,

24. K /ed in the direction of motion

26. (a) 111 ns (b) 5.67 mm (c) (450 i + 102 j) km/s

28. 355 kN m C2⋅ /

30. (a) –55.6 nC (b) negative, with a spherically symmetric distribution

32. (a) 3 20. /MN m C2⋅ (b) 19 2. /MN m C2

⋅

(c) The answer to (a) could change, but the answer to (b) would stay the same.

34. (a) 0 (b) 365 kN/C radially outward(c) 1.46 MN/C outward (d) 649 kN/C radially outward



Chapter 19

104

36. (a) 913 nC (b) 0

38. −2 48. μ C/m2

40. (a) 0 (b) 5 400 N/C outward (c) 540 N/C outward

42. (a) 248 nC/m2 (b) 496 nC/m2

44. (a) –λ , +3λ (b) 3 2 0λ π / r radially outward

46. (a) negative 1 06. nC/m2 (b) –542 kC, 3 38 1024. × excess electrons

48. (a) 4.18 kN away from Earth(b) The gravitational force is 4 77 1016. × times stronger and in the opposite direction

50. 0.205 μ C

52. Q Lk L L

k

i

e

=

−( )2

54. 0.0729 a

56. (–1.36 i + 1.96 j) kN/C

58. See the solution

60. (a) 0 (b) σ /0 to the right (c) 0




Chapter 20

135


2. 1.35 MJ

4. (a) 81.6 Mm/s (b) 83.9 Mm/s, too large by 2.91%

6. 1.67 MN/C

8. (a) 59.0 V (b) 4 55 106. × m/s

10. (a) 1 44 10 7. × − V (b) − × −7 19 10 8. V

(c) − × + ×− −1 44 10 7 19 107 8. .V, V

12. (a) –4.83 m (b) 0.667 m and –2.00 m

14. (a) –27.2 eV (b) –6.80 eV (c) 0

16. (a) 32.2 kV (b) − × −9 65 10 2. J

18. (a) no point at a finite distance from the charges (b) 2k q ae /

20. (a) vm k q q

m m m r r de

12 1 2

1 1 2 1 2

2 1 1=

+( ) +−

⎛ ⎝ ⎜

⎞ ⎠ ⎟ v

m k q q

m m m r r de

21 1 2

2 1 2 1 2

2 1 1=

+( ) +−

⎛ ⎝ ⎜

⎞ ⎠ ⎟

(b) Faster than calculated in (a)

22. (a) –45.0 μ J (b) 34.6 km/s

24. (a) 0 (b) k Q re / 2

26. −0 553. /k Q Re

28. V k L L b L

L b L

e= −⎛ ⎝

⎞ ⎠

( ) + −

( ) + +

⎡

⎣

⎢⎢⎢

⎤

⎦

⎥⎥⎥

α

2

4 2

4 2

2 2

2 2ln

/ /

/ /

30. 1 56 1012

. × electrons removed

32. (a) 135 kV(b) 2.25 MV/m away for the lar ge sphere and 6.74 MV/m away for the small sphere

34. (a) 1 00. Fμ (b) 100 V

36. (a) 1 33 2. C/mμ (b) 13.3 pF



Chapter 20

136

38. (a) 2.68 nF (b) 3.02 kV


42. (a) 3.53 μ F (b) 6.35 V and 2.65 V (c) 31.8 μ C on each

44.1

2

1

4

2C C C Cp p p s± −

46. 12.9 μ F

48. (a) 216 μ J (b) 54.0 μ J

50. (a) stored energy = 0.150 J. See solution for circuit diagram.(b) potential difference = 268 V. See solution for circuit diagram.

52. (a) 1.50 μ C (b) 1.83 kV

54. (a) 81.3 pF (b) 2.40 kV

56. 1.04 m

58. (a) 369 pC (b) 118 pF, 3.12 V (c) –45.5 nJ

60. 9.79 kg

62. (a) ~ 104 V (b) ~10 5− C or ~ 10 6− C

64. Yes; 1 00 106. × m/s

66. (a)

0 2 1

dx+ −( )( )κ (b)

02

2

21

ΔV

dx

( ) + −( )( )κ

(c)

0

2

21

ΔV

d

( ) −( )κ to the left (d) 1 55 10 3. × − N to the left

68.4

3C

70.

23.3 V, 26.7 V


74. (a) 1.42 mm (b) 9.20 kV/m

76. (a) See the solution (b) E k p rr e= 2 3cos /θ E k p reθ θ = sin / 3 ; yes; no

(c) V k py x ye= +( )−2 2 3 2/

E i j= +( ) + −( ) +( )− −

3 22 2 5 2 2 2 2 2 5 2k pxy x y k p y x x ye e

/ /



Chapter 21

162


2. 3.64 h

4. (a) 17.0 A (b) 85 0. kA/m2

6. 0.130 mm/s

8. (a) 1.82 m (b) 280 μ m

10. 1.98 A

12. 1.71 Ω

14. (a) unaffected (b) doubles(c) doubles (d) unchanged

16. 448 A

18. 672 s

20. 295 metric ton/h

22. (a) $1.61 (b) $0.005 82 (c) $0.416

24. (a) 4.59 Ω (b) 8.16%

26. 73.8 W

28. (a) See the solution (b) no

30. (a) 75.0 V (b) 25.0 W, 6.25 W, and 6.25 W; 37.5 W

32. 0.714 A, 1.29 A, 12.6 V




Chapter 21

163

36. 50.0 mA from a to e

38. (a) –61.6 mA (b) 0.235 μ C (c) 1.96 A

40. (a) 1.50 s (b) 1.00 s (c) 200 100 1 00+( )−

e t/ . s Aμ

42. 587 k Ω

44. (a) 300 MW (b) 171 PW

46. (a) 222 μ C (b) increases by 444 μ C

48. (a)V

L i (b)

4

2

ρ

π

L

d (c)

V d

L

π

ρ

2

4

(d) V

Lρ i (e) See the solution


52. (a) 0.991 (b) 0.648(c) Insulation should be added to the ceiling.

54. (a) R →∞ (b) R → 0 (c) R = r

56. (a) 9.93 μ C (b) 33.7 nA(c) 334 nW (d) 337 nW


60. (a) ρ π / ln /2 L r rb a( ) ( ) (b) 2π L V I r rb aΔ ln /( )[ ]



Chapter 22

192


2. (a) 8 67 10 14. × − N (b) 5 19 1013. × m/s2

4. 8 93 10 30. × − N down, 1 60 10 17. × − N up, 4 80 10 17. × − N down

6. (a) 5.00 cm (b) 8 78 106. × m/s

8. 244 kV/m

10. (a) 7 66 107. × rad/s (b) 26.8 Mm/s (c) 3.76 MeV

(d) 3 13 103. × rev (e) 257 μ s

12. (a) See the solution (b) n IB qt V H = / Δ

14. 0.109 A to the right

16. ab: 0, bc: –40.0 mN i , cd: –40.0 mN k , da: (40.0 i + 40.0 k) mN

18. (a) 5 41. mA m2⋅ (b) 4.33 mN⋅m


22. 261 nT into the page

24. 11

2

0+⎛ ⎝

⎞ ⎠ π

μ I

Rdirected into the page


28. μ π 0 2 1 1 4I r/ / /( ) +( ) into the plane of the paper

30. (a) 10.0 μ T out of the page (b) 80.0 μ N toward the first wire(c) 16.0 μ T into the page (d) 80.0 μ N toward the second wire

32. 0.167 m below the upper wire, 0.333 m above the lower wire

34. 5.40 cm



Chapter 22

193

36. (a) 3.60 T (b) 1.94 T

38. 500 A

40. 464 mT

42. (a)μ 0

2 2 2 22

IN a

a R

a

a R

+−

−

−( ) +

⎛

⎝ ⎜⎜

⎞

⎠ ⎟ ⎟

(b) See the solution

44. 2.02

46. (a) 1.4 MJ/mi (b) 5.7 MJ/mi (c) 1/400

48. (a) The electric current feels a magnetic force. (b) See the solution

50. (a) − × −8 00 10 21. kg⋅m/s (b) 8.90°

52. (a) 1 04 10 4. × − m (b) 1 89 10 4. × − m

54. (a) 1.33 m/s(b) No. Positive ions moving toward you in magnetic field to the right feel upward magnetic force,

and migrate upward in the blood vessel. Negative ions moving toward you feel downwardmagnetic force and accumulate at the bottom of this section of vessel. Thus both species canparticipate in the generation of the same emf.


58. (a) 2.46 N up (b) 107 m/s2 up

60. (a) 274 μ T (b) –274 j μ T (c) 1.15 i mN

(d) 0 384 2. i m/s (e) acceleration is constant (f) 0.999 i m/s

62. B k=μ 0

2

J s for x > 0 and B k= −μ 0

2

J s for x < 0


Resoluções de Exercícios Pares - Cap 19 até Cap. 22 - Princípios de Física Vol. 3

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Transcript of Resoluções de Exercícios Pares - Cap 19 até Cap. 22 - Princípios de Física Vol. 3