Exercícios Lagrange

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  • 8/17/2019 Exercícios Lagrange

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    Sec. 3.21

    The vibration of structures with more than two degrees of freedom

    109

    If it is assumed that h, = h,

    ---

    m , m(- 1

    -

    w:

    k o k

    m, 3m

    o

    = h, = h, I I = I, = l3

    =

    Iandm, =

    m2

    =

    m =

    m,

    )

    24

    E l

    m

    (

     

    G

    m

    k

    g

    mh3

    4EI

    In a particular case, m, = 2

    x

    lo6 kg,

    m =

    200

    x lo3

    kg,

    h

    =

    4

    m,

    E =

    200 x lo9N/m2,

    I = 25 x 10 m4 and k, = lo7 N/m.

    Thus

    1

    0:

    (2 x 10') (3 x 200 x 10')

    10'

    200 x 10, x

    4 ,

    4 x 200 x io9 x 25 x

    io

    -

    = 0.26 0.64,

    so that w , = 1.05 rad/s,f, = 0.168 Hz and the period of the oscillation is 5.96

    s.

    3.2.2 The Lagrange equation

    Consideration of the energy in a dynamic system together with the use of the Lagrange

    equation is a very powerful method

    of

    analysis for certain physically complex systems.

    This is an energy method that allows the equations of motion to be written in terms of any

    set of

    generalized coordinates.

    Generalized coordinates are a set of independent para-

    meters that completely specify the system location and that are independent of any

    constraints. The fundamental form of Lagrange's equation can be written in terms of the

    generalized coordinates

    q1

    as follows:

    where T is the total kinetic energy of the system, V is the total potential energy of the

    system, D E is the energy dissipation function when the damping

    is

    linear (it is half the

    rate at which energy is dissipated so that for viscous damping

    D E

    =

    ;cA?* ,

    Qi is a

    generalized external force

    (or

    non-linear damping force) acting on the system, and q is a

    generalized coordinate that describes the position of the system.

    The subscript i denotes n equations for an n degree of freedom system, so that the

    Lagrange equation yields as many equations of motion

    as

    there are degrees

    of

    freedom.

    For a free conservative system Q, and

    D E

    are both zero,

    so

    that

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    110 The vibrat ion

    of

    structures w ith m or e than o ne degree o f freedom

    [Ch

    3

    The full derivation of the Lagrange equation can be found in Vibration Theory and

    Applications by W.

    T.

    Thomson (Allen Unw in, 1989).

    xample 24

    A

    solid cylinder has a mass

    M

    and radius

    R.

    Pinned to the axis of the cylinder is an arm

    of length 1 which carries a bob of mass

    rn

    Obtain the natural frequency of free vibration

    of the bob. The cylinder is free to roll on the fixed horizontal surface shown.

    The generalized coordinates are

    xl

    and

    x,.

    They completely specify the position of the

    system and are independent of any constraints.

    T

    =

    hxi

    f(-hR2)82

    mi;

    = -hi: ; -hi:);mi;.

    v = rngl(1

    -

    cos @)= rng1/2) bZ=

    (rng/21)(x2

    for small values of 4 Apply the Lagrange equation with qi = xl:

    (d/dt)(aT/dil) =

    Mi l

    I.?,

    av/aX = (rng/21)(-2x2 + k, .

    Hence ' XI (rng/l)(xl

    x,)

    =

    0

    is an equation of m otion.

    Apply the Lagrange equation with

    q

    =

    x,:

    (d/dt)(aT/ ,) = m i 2

    av/ax,

    = ( rng /21)(h2-k, ,

    Hence

    m f ,

    (rng/f)(x ,

    x,)

    =

    0

    is an equa tion of motion.

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    Sec. 3.21

    The vibrat ion of structures with m ore than two degrees of f reedom

    111

    These equations of motion can be solved by assuming that

    x ,

    = XI

    inm and

    x , =

    X,sinm. Then

    X1

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    112

    The vibration of structures w ith m or e than on e degree of freedom

    [Ch.

    3

    Now

    apply the Lagrange equation with q = q .

    aT

    ~-

    -

    0.

    and

    Thus the first equation of motion is

    M q l

    2kIql k, b-d)q, =

    0.

    Similarly by putting qi = q2 and qi = q3, he other equations of motion are obtained as

    Mq2 2kIq2 - 2ak2q3 = 0

    and

    I G q 3

    k , ( b

    - d)ql -

    2ak2q2 b2 )k,

    2a2k2q3= 0.

    The system therefore has three coordinate-coupled equations of motion. The natural

    frequencies can be found by substituting

    qi

    =

    A i

    sin

    a,

    nd solving the resulting

    frequency equation. It is usually desirable to have all natural frequencies low so that the

    transmissibility is small throughout the range of frequencies excited.

    E x a m p l e 26

    A two-storey building which has its foundation subjected to translation and rotation is

    modelled by the system shown. Write down expressions for

    T

    and V and indicate how the

    natural frequencies of free vibration may be found using the Lagrange equation.

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    Sec. 3.21

    The vibration of structures with more than two degrees of freedom

    11

    3

    For small-amplitude vibration,

    T

    = ~m ’ i J o 8

    i m l ioh b

    +i, ’ ;.IJ,

    m, i0 2 h b

    i2)‘

    i J 8

    and

    v

    =

    ik,x,2

    4,8‘

    2(;kk,x:

    h2

    X’ XI)’>

    where, x,,

    0

    x, and x 2 are the generalized coordinates. Substituting in the Lagrange

    equation with each coordinate gives four equations of motion to be solved for the

    frequency equation and hence the natural frequencies of free vibration and their associated

    mode shapes.

    3.2.3 Receptance analysis

    Some simplification in the analysis of multi-degree of freedom undamped dynamic

    systems can often be gained by using receptances, particularly if only the natural

    frequencies are required. If a

    harmonic force F

    sin vt acts at some point in a system so that

    the system responds at frequency v, and the point of application of the force has a

    displacement

    x

    =

    X

    sin vt, then if the equations of motion are linear, x =

    a F

    sin vt where

    a which is a function of the system parameters and v, but not a function of

    F,

    is known

    as the direct receptance at x. If the displacement is determined at some point other than

    that at which the force is applied,

    a

    is known as the transfer or cross receptance.

    The analogy with influence coefficients (section 3.2.1) is obvious.

    It can be seen that the frequency at which a receptance becomes infinite is a natural

    frequency of the system. Receptances can be written for rotational and translational

    coordinates in a system, that is, the slope and deflection at a point.

    Thus, if a body of mass

    m

    is subjected to a force

    F

    sin vt and the response of the body

    is x

    = X

    sin

    vt,

    F

    sin

    vt = m s

    =

    m(- XV’

    sin vt)

    =

    - mv’x.

    Thus

    x

    =

    F

    sin vt

    mv’

    and

    a =

    mv”

    This is the direct receptance of a rigid body.

    For a spring, a = Ilk. This is the direct receptance of a spring.

    In an undamped single degree of freedom model of a system, the equation of motion

    is

    mi‘

    kr

    = F sin vt.

    If x = X sin vt, a = l/(k mv’ . This is the direct receptance of a single degree of

    freedom system.